Monday, November 5, 2012

A Redskins loss may prove fateful to the presidential election


Sunday's Carolina Panthers win over the Washington Redskins may very well spell trouble for President Barack Obama and his bid to earn a second term. In fact, according to the dubious "Redskins Rule", Washington's loss should equal a win for Mitt Romney on Election Day.

The so-called Redskins Rule has accurately predicted the result of the presidential elections 17 out of 18 times. What exactly is this rule, you may ask? Well, if the Redskins win their last home game before the election, then the incumbent party retains the White House. However, if the Redskins lose, then the incumbent is voted out.

The rule has been traced all the way back to the 1940 election, which was the first presidential election year in which the 'Skins were playing in Washington. The only exception to the rule was in 2004 when the Redskins lost to the Green Bay Packers. That should have meant incumbent president George W. Bush would lose re-election, but he edged out John Kerry instead to retain his position and end the perfect streak on the Redskins Rule.

But with that being said, a 94.4% accuracy rate is still pretty telling.

One other historical fact that may be in favor of Romney is that Republicans have won every presidential election which has fell on November 6th since Abraham Lincoln was voted into office in 1860. That is six in all.

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